PHP5对Mysql5的任意数据库表的管理代码示例（三）
续：点击编辑一个条目会跳转至edit.php
//edit.php
<html>
<head><title>Editing an entry from the database</title>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
</head>
<body bgcolor=#ffffff>
<h2>Edit an entry</h2>
<?
$database = "sunsite";
$tablename = $_REQUEST;
echo "<h2>Data from $tablename</h2>";
mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");
$query = "show columns from $tablename";
$result = mysql_db_query($database,$query);
$column = 0;
if ($result)
{
echo "Found these entries in the database:<br><p></p>";
echo "<table width=90% align=center border=1><tr>";
while ($r = mysql_fetch_array($result))
{
echo "<td align=center bgcolor=#00FFFF>$r</td>";
$colname = $r;
$column = $column + 1;
}
echo "</tr>";
mysql_free_result($result);
$query = "select * from $tablename";
$result = mysql_db_query($database, $query);
if ($result)
while ($r = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td><a href="editing.php?$colname=$r&tablename=$tablename">$r</td>";
for($col=1;$col<$column;$col++) echo "<td>$r</td>";
echo "</tr>";
}
echo "</table>";
}
else echo "No data.";
mysql_free_result($result);
?>
<a href="tables.php?tablename=<? echo "$tablename"?>">Finish</a>
</body>
</html>
然后选择其中一个id，会跳出具体的内容并要求用户修改。
//editing.php
<html>
<head><title>Editing an entry</title>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
</head>
<body bgcolor=#ffffff>
<h1>Editing an entry</h1>
<?
$database = "sunsite";
$tablename = $_GET;
mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");
$query = "show columns from $tablename";
$result = mysql_db_query($database,$query);
$column = 0;
if ($result)
{
while ($r = mysql_fetch_array($result))
{
$colname = $r;
$column = $column + 1;
}
mysql_free_result($result);
}
$temp = $_GET];
$query = "select * from $tablename where $colname=$temp";
$result = mysql_db_query($database,$query);
$r = mysql_fetch_array($result);
?>
<form method="post" action="editdb.php">
<table width=90% align=center>
<tr><td><?php echo "$colname";?>:</td><td><?php echo "$r"; ?></td></tr>
<?
for ($col=1;$col<$column;$col++)
echo "<tr><td>$colname:</td><td><input type=text name=$colname size="100%" value="$r"></td></tr>";
?>
<input type=hidden name=id value="<?php echo "$r"; ?>">
<input type=hidden name=tablename value="<?php echo"$tablename";?>">
<tr><td></td><td><input type=submit value="Confirm!"></td></tr>
</table>
</form>
</body>
</html>
最后是写入数据库
//editdb.php
<?
$database = "sunsite";
$tablename = $_POST;
mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");
$query = "show columns from $tablename";
$result = mysql_db_query($database,$query);
$column = 0;
if ($result)
{
while ($r = mysql_fetch_array($result))
{
$colname = $r;
$column = $column + 1;
}
mysql_free_result($result);
}
for($col=0;$col<$column;$col++)
$para = $_POST];
if ($_POST)
{
mysql_connect("localhost","root","") or die ("Problem connecting to DataBase");
$query = "update $tablename set $colname="$para"";
for($col=2;$col<$column;$col++)
$query = $query . ",$colname="$para"";
$query = $query . " where $colname="$para";";
$result = mysql_db_query($database, $query);
Header("Location: edit.php?tablename=$tablename");
}
else
{
echo "No name Entered. Please go back and reenter name";
}
?>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
待续。
-
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